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Timeline for How to read data from a Vector

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S Dec 15, 2021 at 19:29 vote accept Omar
S Dec 15, 2021 at 19:29 vote accept Omar
S Dec 15, 2021 at 19:29
Dec 2, 2021 at 14:42 review Close votes
Dec 6, 2021 at 0:06
Dec 2, 2021 at 14:41 vote accept Omar
S Dec 15, 2021 at 19:29
Dec 2, 2021 at 14:36 comment added molbdnilo Read the introduction to iterators in your favourite C++ book.
Dec 2, 2021 at 14:36 answer added Slava timeline score: 2
Dec 2, 2021 at 14:30 answer added Caleth timeline score: 3
Dec 2, 2021 at 14:30 comment added Abdur Rakib With size_t it's far easier to loop without error. Simply vector_name[i] will give the value at i index.
Dec 2, 2021 at 14:29 comment added Slava @AbdurRakib in this case it is not, OP declared it as an int
Dec 2, 2021 at 14:29 comment added 001 Side note: I find range based for loops easier to work with: for (auto b : Verification) { ... }
Dec 2, 2021 at 14:29 comment added Abdur Rakib Also it is iterator. Kinda like pointer. So, change it==true to *it==true.
Dec 2, 2021 at 14:28 comment added Omar @AbdurRakib that does look a lot better but what do I check for true or false in that for loop
Dec 2, 2021 at 14:28 comment added Caleth Aside: *it==true is the same as *it, is the same as (*it == true) == true. Just use the bool value directly
Dec 2, 2021 at 14:27 comment added Abdur Rakib I don't think the error is the operator. You are declaring it as int but trying to put an iterator in it. Change int to vector<bool>::iterator. Although, personally I prefer this style- for(size_t i = 0; i < vector_name.size(); i++)
Dec 2, 2021 at 14:27 answer added Richard timeline score: 1
Dec 2, 2021 at 14:26 comment added Caleth int it = Verification.begin() should be a compile error too.
Dec 2, 2021 at 14:26 comment added Borgleader *it, an iterator itself is not true or false it points to an element of the container that may be true or false, also your iterator shouldnt be an int
Dec 2, 2021 at 14:23 history asked Omar CC BY-SA 4.0
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