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Formatting; more idiomatic Python
Source Link
Mark Dickinson
Mark Dickinson

find square-root of a number

while True:
  num = int(input("Enter a number:\n>>"))
  for i in range(2, num):
    cond = (num % i == 0)
    if(cond == True):
      # print(I)
      k = (i*i == num)
      if(k == True):
        print("Square root of", num, "==>", i)
        break
  else:
      kd = (num**0.5)   # (num**(1/2))
      print("Square root of", num, "==>", kd)

while True:
    num = int(input("Enter a number:\n>>"))
    for i in range(2, num):
        if num % i == 0:
            if i*i == num:
                print("Square root of", num, "==>", i)
                break
    else:
        kd = (num**0.5)  # (num**(1/2))
        print("Square root of", num, "==>", kd)

OUTPUT:-

Enter a number: 24
Square root of 24 ==> 4.898979485566356
Enter a number: 36
Square root of 36 ==> 6
Enter a number: 49
Square root of 49 ==> 7

✔ Output 💡 CLICK BELOW & SEE ✔

Output1

Output2

find square-root of a number

while True:
  num = int(input("Enter a number:\n>>"))
  for i in range(2, num):
    cond = (num % i == 0)
    if(cond == True):
      # print(I)
      k = (i*i == num)
      if(k == True):
        print("Square root of", num, "==>", i)
        break
  else:
      kd = (num**0.5)   # (num**(1/2))
      print("Square root of", num, "==>", kd)

OUTPUT:-

Enter a number: 24
Square root of 24 ==> 4.898979485566356
Enter a number: 36
Square root of 36 ==> 6
Enter a number: 49
Square root of 49 ==> 7

✔ Output 💡 CLICK BELOW & SEE ✔

Output1

Output2

find square-root of a number

while True:
    num = int(input("Enter a number:\n>>"))
    for i in range(2, num):
        if num % i == 0:
            if i*i == num:
                print("Square root of", num, "==>", i)
                break
    else:
        kd = (num**0.5)  # (num**(1/2))
        print("Square root of", num, "==>", kd)

OUTPUT:-

Enter a number: 24
Square root of 24 ==> 4.898979485566356
Enter a number: 36
Square root of 36 ==> 6
Enter a number: 49
Square root of 49 ==> 7

✔ Output 💡 CLICK BELOW & SEE ✔

Output1

Output2

Attached the code and output both click on output and see 👆✔
Source Link
Shubham-Misal
Shubham-Misal

find square-root of a number

while True:
  num = int(input("Enter a number:\n>>"))
  for i in range(2, num):
    cond = (num % i == 0)
    if(cond == True):
      # print(I)
      k = (i*i == num)
      if(k == True):
        print("Square root of", num, "==>", i)
        break
    else:
      kd = (num**0.5)   # (num**(1/2))
      print("Square root of", num, "==>", kd)

OUTPUT:-

Enter a number: 24
Square root of 24 ==> 4.898979485566356
Enter a number: 36
Square root of 36 ==> 6
Enter a number: 49
Square root of 49 ==> 7

✔ Output 💡 CLICK BELOW & SEE ✔

OutputOutput1

Output2

find square-root of a number

while True:
  num = int(input("Enter a number:\n>>"))
  for i in range(2, num):
    cond = (num % i == 0)
    if(cond == True):
      # print(I)
      k = (i*i == num)
      if(k == True):
        print("Square root of", num, "==>", i)
        break
    else:
      kd = (num**0.5)   # (num**(1/2))
      print("Square root of", num, "==>", kd)

OUTPUT:-

Enter a number: 24
Square root of 24 ==> 4.898979485566356
Enter a number: 36
Square root of 36 ==> 6
Enter a number: 49
Square root of 49 ==> 7

Output

find square-root of a number

while True:
  num = int(input("Enter a number:\n>>"))
  for i in range(2, num):
    cond = (num % i == 0)
    if(cond == True):
      # print(I)
      k = (i*i == num)
      if(k == True):
        print("Square root of", num, "==>", i)
        break
  else:
      kd = (num**0.5)   # (num**(1/2))
      print("Square root of", num, "==>", kd)

OUTPUT:-

Enter a number: 24
Square root of 24 ==> 4.898979485566356
Enter a number: 36
Square root of 36 ==> 6
Enter a number: 49
Square root of 49 ==> 7

✔ Output 💡 CLICK BELOW & SEE ✔

Output1

Output2

Attached the code and output both
Source Link
Shubham-Misal
Shubham-Misal

find square-root of a number

# find square-root of a number
while True:
  num = int(input("Enter a number:\n>>"))
  for i in range(2, num):
    cond = (num % i == 0)
    if(cond == True):
      # print(I)
      k = (i*i == num)
      if(k == True):
        print("Square root of", num, "==>", i)
        break
    else:
      kd = (num**0.5)   # (num**(1/2))
      print("Square root of", num, "==>", kd)

OUTPUT:-

Enter a number: 24
Square root of 24 ==> 4.898979485566356
Enter a number: 36
Square root of 36 ==> 6
Enter a number: 49
Square root of 49 ==> 7

Output

# find square-root of a number
while True:
  num = int(input("Enter a number:\n>>"))
  for i in range(2, num):
    cond = (num % i == 0)
    if(cond == True):
      # print(I)
      k = (i*i == num)
      if(k == True):
        print("Square root of", num, "==>", i)
        break
    else:
      kd = (num**0.5)   # (num**(1/2))
      print("Square root of", num, "==>", kd)

OUTPUT:-

Enter a number: 24
Square root of 24 ==> 4.898979485566356
Enter a number: 36
Square root of 36 ==> 6
Enter a number: 49
Square root of 49 ==> 7

find square-root of a number

while True:
  num = int(input("Enter a number:\n>>"))
  for i in range(2, num):
    cond = (num % i == 0)
    if(cond == True):
      # print(I)
      k = (i*i == num)
      if(k == True):
        print("Square root of", num, "==>", i)
        break
    else:
      kd = (num**0.5)   # (num**(1/2))
      print("Square root of", num, "==>", kd)

OUTPUT:-

Enter a number: 24
Square root of 24 ==> 4.898979485566356
Enter a number: 36
Square root of 36 ==> 6
Enter a number: 49
Square root of 49 ==> 7

Output

OUTPUT
Source Link
Shubham-Misal
Shubham-Misal
Source Link
Shubham-Misal
Shubham-Misal
lang-py